4^x+2=256
You asked:
Solve the equation \({4}^{x} + 2 = 256\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(254 \right)}}{\log{\left(4 \right)}} \approx 3.9943423\]
4^x+2=256
You asked:
MathBot Answer:
The solution is: \[x = \frac{\log{\left(254 \right)}}{\log{\left(4 \right)}} \approx 3.9943423\]