(1/2)(2+(2+0.8t))(t)

asked by guest
on Mar 30, 2025 at 5:42 am



You asked:

Evaluate the expression: 12(2+2+0.8t)⋅t\frac{1}{2} \left(2 + 2 + 0.8 t\right) \cdot t

MathBot Answer:

Evaluated



12(2+2+0.8t)⋅t=t(4t5+4)2\displaystyle \frac{1}{2} \left(2 + 2 + 0.8 t\right) \cdot t = \frac{t \left(\frac{4 t}{5} + 4\right)}{2}

Expanded

12(2+2+0.8t)⋅t=2t25+2t\frac{1}{2} \left(2 + 2 + 0.8 t\right) \cdot t = \frac{2 t^{2}}{5} + 2 t

Factored

12(2+2+0.8t)⋅t=2t(t+5)5\frac{1}{2} \left(2 + 2 + 0.8 t\right) \cdot t = \frac{2 t \left(t + 5\right)}{5}

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