(2÷2/3)-(2/3÷2)
asked by guest on Mar 21, 2025 at 5:25 pm
You asked:
MathBot Answer:
223−232=0\frac{\frac{2}{2}}{3} - \frac{\frac{2}{3}}{2} = 0322−232=0
223−232=13−232=13−13=0\begin{aligned}\frac{\frac{2}{2}}{3} - \frac{\frac{2}{3}}{2}&=\frac{1}{3} - \frac{\frac{2}{3}}{2}\\&=\frac{1}{3} - \frac{1}{3}\\&=0\end{aligned}322−232=31−232=31−31=0