x^3+4x^2+9x+6=0
You asked:
Solve the equation \({x}^{3} + 4 \cdot {x}^{2} + 9 x + 6 = 0\) for the variable \(x\).
MathBot Answer:
The 3 solutions to the equation are: \[\begin{aligned}x &= -1\\x &= - \frac{3}{2} - \frac{\sqrt{15} i}{2} \approx -1.5 -1.9364917 i\\x &= - \frac{3}{2} + \frac{\sqrt{15} i}{2} \approx -1.5 + 1.9364917 i\end{aligned}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).