x^2+y^2=12
x-y=4
You asked:
Solve the system of equations:\[\begin{aligned}{x}^{2} + {y}^{2} &= 12\\x - y &= 4\end{aligned}\]
MathBot Answer:
The system of equations has \(2\) solutions.
\[x = \sqrt{2} + 2, y = -2 + \sqrt{2}\]\[x = 2 - \sqrt{2}, y = -2 - \sqrt{2}\]