\frac{d}{dx}\left(\sqrt{25-x^2-y^2}\right)

asked by guest
on Jul 03, 2024 at 3:55 pm

You asked:

Evaluate the expression: \(\frac{d}{dx}\left[\sqrt{25 - {x}^{2} - {y}^{2}}\right]\)

MathBot Answer:

\[\frac{d}{dx}\left[\sqrt{25 - {x}^{2} - {y}^{2}}\right] = - \frac{x}{\sqrt{- x^{2} - y^{2} + 25}}\]

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