∫0pi(sin(x))dx\int_{0}^{pi}(sin(x)) dx∫0pi(sin(x))dx
asked by guest on Apr 13, 2025 at 12:00 pm
You asked:
MathBot Answer:
∫0πsin(x)dx=2\int_{0}^{\pi}{\sin\left( x \right)}dx = 2∫0πsin(x)dx=2