if a=5,b=10,c=15
(2ab-45)divided by 5
asked by guest on Nov 26, 2024 at 8:34 pm
MathBot Answer:
2ab−455=11\frac{2 a b - 45}{5} = 1152ab−45=11
2ab−455=2⋅10⋅5−455=100−455=11\begin{aligned}\frac{2 a b - 45}{5}&=\frac{2 \cdot 10 \cdot 5 - 45}{5}\\&=\frac{100 - 45}{5}\\&=11\end{aligned}52ab−45=52⋅10⋅5−45=5100−45=11
