$$\sum_{k=1}^{n=1}{(-1)^{k-1}k^2=(-1)^{n-1}[n(n+1)/2]}$$
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
$$\sum_{k=1}^{n=1}{(-1)^{k-1}k^2=(-1)^{n-1}[n(n+1)/2]}$$
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.