x+2y=23
x+y+z=33
x+2z=43
find value of x,y and z
You asked:
Given \( x + 2 y = 23 \), \( x + y + z = 33 \), \( x + 2 z = 43 \), evaluate \( x \), \( y \), \( z \).
MathBot Answer:
The system of linear equations has infinitely many solutions.
\(y\), \(z\) are free variables.
\[x = 43 - 2 z\]
\[y = z - 10\]
\[z = y + 10\]