(x-3)^2+(y+2)^2=36
You asked:
Investigate the equation: \({\left( x - 3 \right)}^{2} + {\left( y + 2 \right)}^{2} = 36\).
MathBot Answer:
The graph of the equation \({\left( x - 3 \right)}^{2} + {\left( y + 2 \right)}^{2} = 36\) is a circle.
The coordinates of its center are \(\left(3, -2\right)\).
Its radius is \(6\).
The cirlce has parameterization: \[\begin{aligned}x\left(\theta\right) &= 3 + 6 \cos{\left(\theta \right)}\\y\left(\theta\right) &= -2 + 6 \sin{\left(\theta \right)}\end{aligned}\]