z+9, z-8

asked by guest
on Sep 23, 2024 at 9:13 am



MathBot Answer:

The sum of \(z + 9\) and \(z - 8\) is:

\[\begin{aligned}&=\left(z + 9\right) + \left(z - 8\right) \\\\ &= 2 z + 1 \\\\\end{aligned}\]

The difference of \(z + 9\) and \(z - 8\) is:

\[\begin{aligned}&=\left(z + 9\right) - \left(z - 8\right) \\\\ &= 17 \\\\\end{aligned}\]

The product of \(z + 9\) and \(z - 8\) is:

\[\begin{aligned}&=\left(z + 9\right) \cdot \left(z - 8\right) \\\\ &= z^{2} + z - 72 \\\\\end{aligned}\]

The quotient of \(z + 9\) and \(z - 8\) is:

\[\begin{aligned}&= \frac{\left(z + 9\right)}{\left(z - 8\right)} \\\\ &= \frac{z + 9}{z - 8} \\\\\end{aligned}\]

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