px^3 + (p + q)x^2 + (q + r)x + r = 0

asked by guest
on Mar 28, 2025 at 2:58 am



You asked:

Investigate the equation: px3+(p+q)⋅x2+(q+r)⋅x+r=0p {x}^{3} + \left(p + q\right) \cdot {x}^{2} + \left(q + r\right) \cdot x + r = 0.

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