[(2x-1)²]²

asked by guest
on Mar 30, 2025 at 9:15 pm



You asked:

Evaluate the expression: (2x−1)22{{\left( 2 x - 1 \right)}^{2}}^{2}

MathBot Answer:

Evaluated



(2x−1)22=(2x−1)4\displaystyle {{\left( 2 x - 1 \right)}^{2}}^{2} = \left(2 x - 1\right)^{4}

Expanded

(2x−1)22=16x4−32x3+24x2−8x+1{{\left( 2 x - 1 \right)}^{2}}^{2} = 16 x^{4} - 32 x^{3} + 24 x^{2} - 8 x + 1

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