3x-2y=0
x-3y+7
asked by guest on Mar 16, 2025 at 7:47 am
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MathBot Answer:
x−3y+7=(−1)3y+2y3+7x - 3 y + 7 = \left(-1\right) 3 y + \frac{2 y}{3} + 7x−3y+7=(−1)3y+32y+7
3x−2y=03 x - 2 y = 03x−2y=0Solve for xxx: x=2y3x = \frac{2 y}{3}x=32ySubstitute xxx into the given expression: x−3y+7=−3y+7+2y3x−3y+7=(−1)3y+2y3+7\begin{aligned}x - 3 y + 7 &= - 3 y + 7 + \frac{2 y}{3} \\ x - 3 y + 7 &= \left(-1\right) 3 y + \frac{2 y}{3} + 7\end{aligned}x−3y+7x−3y+7=−3y+7+32y=(−1)3y+32y+7