3x-2y=0

x-3y+7

asked by guest
on Mar 16, 2025 at 7:47 am



You asked:

Given 3x2y=03 x - 2 y = 0 evaluate the expression x3y+7x - 3 y + 7.

MathBot Answer:

x3y+7=(1)3y+2y3+7x - 3 y + 7 = \left(-1\right) 3 y + \frac{2 y}{3} + 7


3x2y=03 x - 2 y = 0Solve for xx: x=2y3x = \frac{2 y}{3}Substitute xx into the given expression: x3y+7=3y+7+2y3x3y+7=(1)3y+2y3+7\begin{aligned}x - 3 y + 7 &= - 3 y + 7 + \frac{2 y}{3} \\ x - 3 y + 7 &= \left(-1\right) 3 y + \frac{2 y}{3} + 7\end{aligned}