TAN 60+SIN 60

asked by guest
on Jan 22, 2025 at 5:41 am



You asked:

Evaluate the expression: tan⁡(60)+sin⁡(60)\tan\left( 60 \right) + \sin\left( 60 \right)

MathBot Answer:

tan⁡(60)+sin⁡(60)=sin⁡(60)+tan⁡(60)≈0.01522976827734626931253815422728\tan\left( 60 \right) + \sin\left( 60 \right) = \sin{\left(60 \right)} + \tan{\left(60 \right)} \approx 0.01522976827734626931253815422728

tan⁡(60)+sin⁡(60)=tan⁡(60)+sin⁡(60)=sin⁡(60)+tan⁡(60)\begin{aligned}\tan\left( 60 \right) + \sin\left( 60 \right)&=\tan{\left(60 \right)} + \sin{\left(60 \right)}\\&=\sin{\left(60 \right)} + \tan{\left(60 \right)}\end{aligned}

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