solve this by graphing y=-7/2x-2 and y=-2x+1
solve x for 9x^{4}+36x^{2}+210
If the 2nd and 5th terms of a G.P are 6 and 48 respectively, find the sum of the first four for term
4X-10=8-2X
1/4 3/2 5/8 9/4
$$\int_{\}^{\}\(1/((x-2)^2(x^2-4x+5))) d\(x)$$
(z/(1-z))(z/(37,8+z))^(1/2)=0,3273407
$$\int_{1}^{2}(\x^2) d\x$$
10 − 5x = 10
1 PORCIENTO A GRADO
