simplify the ratio 1/3: 1/8: 1/6
find the nth term of the sequence -3,-10,-17, -24
J n (x+y)= sum r = - ∞ to ∞ J r (x)J n-r (y)
f(x)=/x/-5
domain and range
37 And A²+48-45 iP A = [[3, - 2], [1, 0]] A = [[1, - 1], [2, - 2]]
1rt
neia
473÷9
\quad \log_{49}{\left(7\right)}=\dfrac{1}2
Reescreva a seguinte equação na forma logarítmica.
\[\quad 64=4\^{ \Large{{3}}}\]
$a^{3}$ - $a^{2}$
(x+6)-(5-2x)+2=0