solve 3*3-3/3
+3
find the value of n
7 divided by n = 42/1
-20(-20)
(-20) . (-20)
-20-20
6 divided by n = 18/1
2/y - 3/y + 1 = 3
f(x) = 5 sin (2 $$\sum_{a}^{b}{C}$$ $$\prod_{a}^{b}{C}$$ x + $$\prod_{a}^{b}{C}$$ divided by 2)
[4]−2019 and [7]−1010 in (Z15,×15)
6/2(1+2)