5 - 0.18
25= $\sqrt{3}$ x25a^2 what is the value of "a"
the second term of a geometric sequence is 12. The fourth term is 108.What is the fifth term
25= $\sqrt{3}$ x25a^2
(t^3/u^5)^2
calcule l'intégrale de d= [2,0] ((2x-1)/ (x^2-x+1)) dx
@INTEGRAL{}@DIV{4;x@Sup{5}}@RT{7-@DIV{1;4}}dx
SIMPLIFY
4pn * 2p^4
Given f(x) = 3 x²and g(x) = (2x-3) Find (g of) (4)?
(3x+2)(3x+2)
