6sin^2(x)-7cos(x)-8=0
find the smallest positive multiple of 198 such that its digits are made up of only 1s and 2s
18a $^{2}$bc + 30ab$c^{2}$
6(sin^2)(x)-7cos(x)-8=0
8(10-x) over (x+1)(x-10) divided by x-8 over (x-8)(x+1)
6(sin(x))^2-7cos(x)-8=0
$\infty$- $\infty$
5x+ 6x-5=
faça a árvore rubro negra com os seguintes numeros [20, 10, 12, 22, 35, 31]
-1/46-1/66