log5 (25) x log5 (5)
(a^3 x a^-2 x a^4)^-2
log5 (25) - log5 (5)
\begin{aligned}
7x+10y&=60 \\\\
7x-2y&=240
\end{aligned}
(3/4)*{(1/3)*[8^2+(24/6*4)+10]+[(2/5)*(10^2-12+3)]}
log10 (1000) - log10 (10)
log3 (9) - log3 (3)
log3 (9) + log3 (3)
if cosx+sinx=4/3 find 2x and cos 4x
(3/4).*{(1/3).*[8^2+(24/6*4)+10]+[(2/5).*(10^2-12+3)]}
