find a solution to x^2 = 17 mod 128
-20/10
2 x ((6 minus 5 plus 3 squared ) plus 4 squared)
find a solution to x^2 is congruent to 17 mod 128
3x + 2y = -2 , 4x + 6y = -4 find x and y
2x$^{3}$−7x$^{3}$ +2x−7=0
f(x)=2x+3+c
2x+2y-z=0 x-2y+z=2 x+y=0
How to solve 4x = 2x + 6 using balance method
0.83+0.62
