p-3q=7
$4x^{2}$ +2=0
=10,00,000 * 0.006 * (1 + 0.006)120 / ((1 + 0.006)120 - 1)
10,00,000 * 0.006 * (1 + 0.006)120 / ((1 + 0.006)120 - 1)
$3x^{2}$ +2y=7
2x+5 < (x+1)/4
if the squrre base pyramid tsa is 144 and slant height is 5 then find the length of base
3y+7 <= 2-y
x(2-3x)=4y
15x-43 < 5x+2