9 - 2√ -36
x^2 - x = 6
(x-2y)dx+(2x+y+5)dy=0
9 - 2√-36 = 3
lim (secx/tanx)/ $\pi$ /2-x
x- $\pi$ /2
9 - 2√-36 =
1/4+3/5
3x-y=3y-1, solve in terms of y
($x^{2}$+1)/($x^{2}$-4)
9 - 2√-36
