simplify 3 1/8+4 1/2+5 3/10
If,a^2-√3a+1=0 and a is an positive no.Prove that,a^4-a^2+1=0
{9-(45/9-3)*2}-5
315*1/3
$\lim_{x \rightarrow +\infty} (1 + \frac{1}{x})^{x^2}$
30/(150)2
Make Q subject in this Equation
-Q^2-4Q+45=0
56 ÷24÷4+7×5-9×3
__x6 divided by 3=40
