$$\begin{bmatrix} -1 & y+6 \\\\ x-4 & 3 \end{bmatrix}$$ = $$\begin{bmatrix} -1 & 8 \\\\ -9 & 3 \end{bmatrix}$$
$3$ to the second
WHAT IS the rdeco;ieh;
2x + 5y = 210
$$\begin{bmatrix} -6 & 1 \\\\ 9 & 2 \end{bmatrix}$$ $$\begin{bmatrix} 3 & 0 \\\\ -3 & 4 \end{bmatrix}$$
differentiate first principle y=x^2-4x
solve for a
a-1=a^2+1
-4 $$\begin{bmatrix} 1 & 10 \\\\ -4 & -6\end{bmatrix}$$ - $$\begin{bmatrix} 4 & 8 \\\\ -3 & -8 \end{bmatrix}$$
0.25 $$\begin{bmatrix} 8 & 20 & -12\\\\ -8 & -4 & 36 \end{bmatrix}$$
$$\begin{bmatrix} 2 & 5 & -4 \\\\ 3 & 0 & -2 \end{bmatrix}$$ + $$\begin{bmatrix} 3 & 2 & 7 \\\\ -2 & -5 & 7 \end{bmatrix}$$
