$\frac{8a^2+4a+2 \}{2a+3\}$ ÷ $\frac{8a^3 - 1\}{4a^2 + 12a + 9\}$
\[-7\leq x\leq 2\]?
(1 + 0.006)120
7/2
Verify: -(-x) = +x, if x = -5/13
Simplify:
3/4 + -7/12 + 13/24
7a ouestion no 1 to 10
3 7 13
4 12 2
Re(z)<-1
log101 = 0