0,00,000 * 0.006 * (1 + 0.006)120 / ((1 + 0.006)120 - 1) = ₹11,714.
$3x_{2}$ +2y=7
2x+4=2
(x-2)(x+2) over (x-3)(x-1)
20x+50y
16<2x-5<48
find the nth term if the number sequence goes ((1)power2)+2, ((2)power2)+5, ((3)power2)+8 and ((4)power2)+11
x + 2 = 0
(2x-3)/5 - x/3 <=2