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in triangle abc ab=3 cm,bc=2.6 ca=1.7 then the angles of a triangle in ascending order
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in triangle abc ab=3 cm,bc=2.6 x=1.7 then the angles of a triangle in ascending order
a=πr^2
d=2r
A=1/4πd^2=1/4 x π x 6^2
A=1/4πd^2=1/4xπx6^2
5/12 - 1 /3
26+24x=2
n ÷ mr + 3
for m = 2, n = 8, and r = 3.
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