x+4=0
$\sqrt{\Box}$ 4x=6
x
2−x−6
x+1
≤ 0 solve and find its Zeroes of both numerator and denominator
b. Test points (Solve)
c. Graph
d. Intervals ...
x-5=(-2x+10)/2
solve this by graphing y=-7/2x-2 and y=-2x+1
solve x for 9x^{4}+36x^{2}+210
If the 2nd and 5th terms of a G.P are 6 and 48 respectively, find the sum of the first four for term
4X-10=8-2X
1/4 3/2 5/8 9/4
$$\int_{\}^{\}\(1/((x-2)^2(x^2-4x+5))) d\(x)$$
