n : 3 = 12 : 18
∫(1-u^2/c^2)^(-3/2)du
12 : 36 = 24 : n
y=(x-4)(x-2)
6 : 4 = n : 20
(2x+1) (3x+1) show solution please
(x-1)×(x+1)=24
9 : 12 = n : 36
what number do we obtain when rounding off 49nearest hundred
(2x+1) (3x+1)