Prove that gcd (2𝑎 + 𝑏, 𝑎 + 2𝑏) = 1 𝑜𝑟 3 for all integers 𝑎 and 𝑏.
The solution of the equation 20m/3 = 40 is m =
20,563,592.00 = 2,467,813.50*x
if T= sin (xy/x^2+y^2)+√x^2+y^ by using euler's theorem find x dy/dx xy dt/dy
230 divided by 25 with solution
$a^{8}$ - 2 $a^{4}$ + 1=0
if 25-3x=4 find the value of x
1/3 $\sqrt{0,09}$-0,3 $\sqrt{9/100}$
15 DIVIDED BY 140
divide 3^128 by 5^64
