16/4(3-5)
$$\sum_{a}^{b}{C}$$ ((3x-1)^a) / ((a^3)+a)
b= $\infty$
a=0
3(8-y)=-(y-4)
27 5/9-18 7/9=
5(8-y)=-(y-4)
|0.2x+0.6|<0.15
6(b-2)=5(9+b)
|x+3|<1
sn9 =66°
|2x+5|<0.5