solve 10x-7=5x+8
Square ABCD has vertices A (-4.5,4), B (3.5, 4), C, (3.5, -4), and D (-4.5, -4). What is the area of the square ABCD?
2x-5=5x+1
5=4x+3
5 to the power of -3 in a fraction with no indicies
. Let f(x) = √x + 1 + 4.
(e) The range of f is .
10,005 rounded to 2 decimal places
5x - 5x
2 + 2
m ▫ n = (m + n) 2 - mn Find the value of 5 ▫ 7.
