Evaluate
n\6+2 when n=12
(3x +8)/3 =x -5
(3 +8)/3 =x -5
f(x)=((x-2)/(x^(2)+1))
If A×B={(a,1) (a,2) (a,3) (b,1) (b,2) (b,3) } find the set A and B and hence find B×A
21x+3x=24+2x to x ka value
(x^2 -16x+60)(x-10)
1 - 7/9
(27^2/3-27^-2/3). (16^3/4-16^-3/4)
(5/2, −2 ),( −2, 1/4),(3/2 , − 7/2)