(0.5m^2)/(0.770+0.05m)
2(m + 40) - 6m = 3 (4m - 80 )
0.5m/(0.770x0.05)
y = - $\frac{3}{2}$ x - 1
x = -3
what is the y value
What is the mass of 1.20 x 10^21 atoms of sulfur?
1.20 x 10^21 / (6.02 x 10^23)
√306
1.20 x 10^21 / 6.02 x 10^23
z1-z2=
z1=6+5i
z2=2-3i
