8\times ^0+1
1. Find the first 5 terms of
the given nth term an = (5n+6) + (2n+6)
[(√𝟐 + √𝟑)]^2
$$\begin{bmatrix} 2 & 3 & 4 \\\\ 3 & 1 & 2 \\\\ -1 & 2 & 2 \end{bmatrix}$$ solve row echelon
32.7
x. 3
81 DIVIDED BY 400
By substitute u=x+x‐1, solve, x⁴+4x³+5x²+4x+1=0
31016x+67167y=68
15417x-6248y=264
0/0