tan $^{-1}$ ( $\frac{120}{119}$ ) $\pi$ /4
15/30/2
((5+3)∗2−4)>=(12/3+1)∣∣(10−3)=(8−5∗1)
(3+2)+4=3+(2+4)=3+(4+2)=9 associative property
^y= cc
$\sqt{Bo}$
a^3y=x^4
10-5+7
4 2/3 % of 375
f(x) = 3cos(x)e−2x − 1 = 0
y=x/2
5x+y=11
