6/8 of 4/10
x^5 - 1 = 0
x - 1 = 0
find the coordinates of the parabola y=x^2 that are closest to the cordinate point (34,1/2). d = (x_2-x_1)^2 + (y_2-y_1)^2.
34x5x4x5
4r+5=19-3r
(121a^14b^2)^-1/2
y"=(x²y²)/(1+x³)
r+5=19-3r
