prove that 3√2+√5 is irrational
2/7 into 7/5 $^{3x}$
2/7 into 7/5 $a^{3x}$
3/5 OF 1000
sqrt(x-1+2*sqrt(x-2))+sqrt(x+2+6*sqrt(x-2))=2
sqt(x-1+2sqrt(x-2))+sqrt(x+2+6sqrt(x-2))=2
2/7 * 7/ $5^{3x}$
y=10
4y-7
y=42
50-y+8
how to solve n% of 18=64