If f(x)= 1 − 7x, g(x)= 2x^2 − 6 and h(x)= 3x − 1 / 4x − 9 find:
1. h(1)
cotθ+tanθ=2cosecθ, then find principle value of θ.
solve 3x-cosx-1=0 by newton raphson method correct to 4 decimal places
2. gf(1)
3. gfh(−4)
4. fg(x)
5. gf(x)
6. the value...
(4^k)+(1/(4^k))=(257/16)
100+(0.2y)=y
cos-1(14)(10)
7(x-10)=28
(2k+1)^3 + 5
