$\sqrt{\x}$ = -2
∫ (3 - t)^(3/2) - (3 + t)^(3/2) + 1 dt
Where the limits of integration are: 3 < t < -3
Given the stationary AR(2) process:
X_t=5/6 X_(t-1)-1/6 X_(t-2)+e_t
Find ρ0 , ρ1 and ρ2. ...
2(k-5)+3k=k+6
9xu+6xv-3xw+6uy+4vy-2wy
8.3+10.35/0.007
$y^{2}$ =10y-16
F
roz
=
2
1
⋅1.2kg/m
3
⋅(0.0003m/s)
⋅0.47⋅530.66m
(3b-1)(2b+1)=14
septyni dalint du
