1. ABCD AB = BC, AD = DC. ABD =
68°, ADB = (2y – 7)BDC = 33°, DBC = (3x +
2) 2x + 3y
(a) 118 (b) 114
(c) 104 (d) 108...
6+7(k-3)=-4(1=2k)
6+7k(k-3)=-4(1+2k)
GIVE ME NOTES
(.3)^2 + (.03)^2
minimise Z=6x+21y subject to x+2y>3, x+4y>4, 3x+y>3, x>0, y>0
Use the division algorithm to Find the gcd of 120 and 125.
$$\begin{aligned}3525 &= 60\\ 9110 &= 101\\ 1091 &= 101\end{aligned}$$ Evaluate $5050$.
