$p^{2}+6pq+9q^{2}$
comment calculer AB si AC=4,8 et BC=6
Simplify: $4^{8}$ - $\frac{199\Box}{13\Box}$/6
alshhs
$$\prod_{a}^{b}{C}$$
0.000
0.01
y=x² + 8x + 16
Simplify:
√
14
6
−
4
2
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