According to ACT, results found that students had a mean reading score of 21.4 and standard deviation of 6. Find the probability t...
[ z = \frac{(X - \mu)}{\sigma} ]
$$\int sec(x) dx$$
1285 divided by 18
x=y'+ 2xy = 1n(x), y (1) = 2
y = X^2/3 + 0.9sin (kx) √3-x^2
6 9 over 10 divide 3 over 8
Evaluate : tan2 60º - 2 cosec2 30º - 2 tan2 30º.
5^4/25
