Simplify the following
$2^{x-3}$ / $2^{3}$ =16
1 3/11
1 1/2
5/8(5/8)
$$\sum_{a}^{b}{C}$$ Solve it step by step. 4 power x minus 4 power minus x equals 16. 1 by 16.
4^xx-xxxxx-xx-xx-xxxxx-xx--xx-xx...
95x-114000
$$\prod_{a}^{b}{C}$$ *8*a^3*3
(-3) - (-12) =
In triangle ABC BC=AB Angle B =80 Find angle A
7*15
