(2^x)(3^x)
/(6^x)
solve c if -4=3/7(8)+c
\[ \frac{|k^3 - 1|}{2k^7 + 8} \approx \frac{k3}{2k7} = \frac{1}{2k^4} \]
x^2d^2y/dx^2+xdy/dx+(x^2-v^2) y=0 of order v of bessel function solution
y=arctan(1+4x)
solve for x; x^3 += 125
(2^x)/(6^x)
x^2d^2y/dx^2+xdy/dx+(x^2-v^2) y=0 solutionsolutionbesselsolutionsolutionbesselsolution
expand 15a + 12b
