5x-6/(x+2)(2x-1)(3x+5)
what is the median of the numbers 11,13,15,23,28,29
x5\frac{x}{5}5x + 310\frac{3}{10}103 =
The nth term of a sequence is n^2+6n-8
Work out the position of the first term in the sequence with a value greater than
100.
x5\frac{x}{5}5x + 710\frac{7}{10}107
h8\frac{h }{8}8h + 3h8\frac{3h}{8}83h
y -6 -1 2 2 -1 16
9= 12\frac{1}{2}21 a 323^{2}32
6,000,000
28,000,000
18,000,000
3,750,000 ∑abC\sum_{a}^{b}{C}a∑bC
