18=aĆ·3-12
3(2c+7)=4c+39
3š„ā $\2{\4+2ā6}$ ā3 š„ā2 =0
y=3Lnx, la inversa
22-8x=2x+9
y=3Lnx
(x^2)-((x+0.5)/6)>(x-0.5)(x+0.5)
3/7=-18/n
5(2w+1)Ć·3=11